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Search found 14 matches |
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Mark Holtkamp Replies: 19 Views: 21088 |
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Josele, the parallel extinction doesn't prove it is biaxial, it could still be uniaxial. But it is consistent with Pete's interpretation. If the photograps were taken along the b-axis, you would expec ... | |
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Mark Holtkamp Replies: 19 Views: 21088 |
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Nice, I think this settles it and Pete's first scheme is the correct one. The plechroism also fits, if the polarisation of you screen is horizontal.
What colors do you see if you turn the crystal 90 ... |
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Mark Holtkamp Replies: 19 Views: 21088 |
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Josele, you can just use the cell of Zachariasen (with beta=119°43'), where the best cleavage is {110} and the common twin plane {100}. If you have a textbook with the same cleavage en twin plane you ... | |
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Mark Holtkamp Replies: 19 Views: 21088 |
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Hi guys
The 'old' unit cell in Mindat is from Zachariasen (1930). For the full reference see the link on Mindat's titanite page to: Speer J A, Gibbs G V (1976) (below the crystal structure applet). ... |
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Mark Holtkamp Replies: 8 Views: 10866 |
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These crystals are a combination of a (trigonal) rhombohedron and a pinacoid. Quite common for hematite I think. | |
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Mark Holtkamp Replies: 11 Views: 31835 |
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Long time ago there was an article in Lapis magazine about a pseudo-octahedral crystal from the Juchem quarry in Germany. I also found one for sale on minfind, from Aussig in the Czech Republic.
Th ... |
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Mark Holtkamp Replies: 21 Views: 59530 |
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Yes that is what he does. The projections of the holohedral classes are divided in triangles by the symmetry planes. So you have 48 triangles in the cubic system, but none in the monoclinic and tricli ... | |
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Mark Holtkamp Replies: 21 Views: 59530 |
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Hi Pete,
Yes you're right. it's the same principle. I didn't realise this can be done for all pointgroups. Mark. |
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Mark Holtkamp Replies: 21 Views: 59530 |
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Paul Tambuyser in his book 'Kristalmorfologie' (in Dutch) uses an interesting method to systematically derive all crystal forms. I don't know if this method is used by other authors. It is based on di ... | |
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Mark Holtkamp Replies: 21 Views: 59530 |
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Hi Pablo,
So if I understand correctly you are looking for a way to mathematically derive the 48 forms, or at least prove there are exactly 48 (or 47) My mathematics are not good enough to do eith ... |
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Mark Holtkamp Replies: 1 Views: 7690 |
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Hi Roger,
See this discussion on Mindat: https://www.mindat.org/mesg-9-15201.html (Link normalized by FMF) Mark. |
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Mark Holtkamp Replies: 17 Views: 85715 |
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Thank jou Josele also for spotting the error. You were right after all, it is a twin on [100] !
Mark. |
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Mark Holtkamp Replies: 17 Views: 85715 |
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After more reading I now believe that the tetrahedrite {100} twin doesn't occur in recent literature because it doesn't exist. The images in Strunz and Dana probably were copied from old references a ... | |
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Mark Holtkamp Replies: 17 Views: 85715 |
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Hi all,
Sorry for the confusion and the late reply. The drawings in the original post are from my website, after a bit of research I think the crystal in the first drawing is not a twin on [111] at ... |
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